Pattern7

Program to print pattern as shown in sample output.

Sample Input
5
Sample Output
1
0 1
0 1 0
1 0 1 0
1 0 1 0 1

Solution in	C	JAVA	PYTHON

#include<stdio.h>
int main() {
  int n,num=1;
  scanf("%d",&n);
  for(int row=1;row<=n;row++){
    for(int col=1;col<=row;col++){
      printf("%d",(num++)%2);
      if(col<=row-1){
        printf(" ");
      }
    }
    if(row<=n-1){
      printf("\n");
    }
  }
}

import java.util.Scanner;
public class Pattern7{
  public static void main(String args[]) {
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    int num = 1;
    for(int row=1;row<=n;row++){
      for(int col=1;col<=row;col++){
        System.out.print((num++)%2);
        if(col<=row-1){
          System.out.print(" ");
        }
      }
      if(row<=n-1){
        System.out.println();
      }
    }
  }
}

n = int(input())
num = 1
for row in range(1,n+1):
  for col in range(1,row+1):
    print(num%2,end="")
    num+=1
    if col<row:
      print(" ",end="")
  if row<n:
    print()