Spiral Matrix

Program to print matrix in Spiral form.

Solution in C    PYTHON

#include<stdio.h>
int main() {
  int mtrx[10][10], rows, cols, i, j, l, t, r, b;
  scanf("%d %d",&rows,&cols);
  for(i=0;i<rows;i++)
    for(j=0;j<cols;j++)
      scanf("%d",&mtrx[i][j]);
  l = 0;
  t = cols-1;
  r = rows-1;
  b = 0;
  i = 0;
  while(i<rows*cols){
    //The following loop reads left to right
    //Constant row index, Increment column index
    for(j=l;j<t+1;j++){
      printf("%d ",mtrx[l][j]);
      i+=1;
    }
    l+=1;
    if(i==rows*cols)
      break;

    //The following loop reads top to bottom
    //Increment row index, Constant column index
    for(j=l;j<r+1;j++){
      printf("%d ",mtrx[j][t]);
      i+=1;
    }
    t-=1;
    if(i==rows*cols)
      break;

    //The following loop reads right to left
    //Constant row index, Decrement column index
    for(j=t;j>b-1;j--){
      printf("%d ",mtrx[r][j]);
      i+=1;
    }
    r-=1;
    if(i==rows*cols)
      break;

    //The following loop reads bottom to top
    //Decrement row index, Constant column index
    for(j=r;j>l-1;j--){
      printf("%d ",mtrx[j][b]);
      i+=1;
    }
    b+=1;
    if(i==rows*cols)
      break;
  }
  return 0;
}

rows, cols= map(int, input().split())
mtrx = []
for i in range(rows):
  mtrx.append(list(map(int,input().split()))[:cols])
l = 0
t = cols-1
r = rows-1
b = 0
i = 0
while i<rows*cols:
  #The following loop reads left to right
  #Constant row index, Increment column index
  for j in range(l,t+1):
    print(mtrx[l][j],end=" ")
    i+=1
  l+=1
  if i==rows*cols:
    break

  #The following loop reads top to bottom
  #Increment row index, Constant column index
  for j in range(l,r+1):
    print(mtrx[j][t],end=" ")
    i+=1
  t-=1
  if i==rows*cols:
    break

  #The following loop reads right to left
  #Constant row index, Decrement column index
  for j in range(t,b-1,-1):
    print(mtrx[r][j],end=" ")
    i+=1
  r-=1
  if i==rows*cols:
    break

  #The following loop reads bottom to top
  #Decrement row index, Constant column index
  for j in range(r,l-1,-1):
    print(mtrx[j][b],end=" ")
    i+=1
  b+=1
  if i==rows*cols:
    break

Input
4 4
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
Output
1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10