2‟s complement of a number
is obtained by scanning it from right to left and complementing all the bits
after the first appearance of a 1. Thus 2‟s complement of 11100 is
00100. Write a C program to find the 2‟s complement of a binary
number.
SOURCE CODE:
/*Program to find 2's complement of a given binary number.*/
#include<stdio.h>
#include<conio.h>
void main()
{
int a[10],b[10],i,j,n;
clrscr();
printf("\nEnter number of bits::\n");
scanf("%d",&n);
printf("\nEnter %d bits::\n",n);
for(i=0;i<n;i++)
scanf("%d",&a[i]);
for(i=n-1,j=0;i>=0;i--,j++)
{
if(a[i]!=1)
b[j]=a[i];
else
{
b[j]=a[i];
i--;
j++;
for(;i>=0;i--,j++)
{
if(a[i]==1)
b[j]=0;
else
b[j]=1;
}
}
}
printf("\nTwo's complement of given binary number is::\n");
for(j=n-1;j>=0;j--)
printf("%d",b[j]);
}
OUTPUT:
Write a C program to find the roots of a quadratic
equation.
SOURCE CODE:
/*Program to find roots of given quadratic equation.*/
#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
double a,b,c,d,r1,r2,real,imag;
clrscr();
printf("\nEnter a,b and c values:\n");
scanf("%lf%lf%lf",&a,&b,&c);
d=(b*b)-(4*a*c);
if(d>0)
{
r1=(-b+sqrt(d))/(2*a);
r2=(-b-sqrt(d))/(2*a);
printf("\nRoots are:\n r1=%.2lf\tr2=%.2lf",r1,r2);
}
else
if(d==0)
{
r1=(-b)/(2*a);
r2=(-b)/(2*a);
printf("\nRoots are:\n r1=%.2lf\tr2=%.2lf",r1,r2);
}
else
{
real=(-b)/(2*a);
imag=(sqrt(d))/(2*a);
printf("\nRoots are:\n r1=%.2lf+i%.2lf\tr2=%.2lf-i%.2lf",real,imag,real,imag);
}
}
OUTPUT:
Write a C program, which takes two integer operands
and one operator form the user, performs the operation and then prints the
result. (Consider the operators +,-,*, /, % and use Switch Statement)
SOURCE CODE:
/*Program to perform arthmetic operation between two numbers.*/
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
char op;
clrscr();
printf("\nEnter a and b values:\n");
scanf("%d%d",&a,&b);
printf("\nEnter operator:\n");
op=getche();
switch(op)
{
case '+':printf("\na+b=%d",a+b);
break;
case '-':printf("\na-b=%d",a-b);
break;
case '*':printf("\na*b=%d",a*b);
break;
case '/':printf("\na/b=%d",a/b);
break;
case '%':printf("\na%%b=%d",a%b);
break;
default:printf("\nWrong Arthmetic Operator.");
}
}
OUTPUT:
